[Python] 프로그래머스 : 대충 만든 자판 160586, enumerate, dictionary

 

 

📝 문제

 

 

🫠 나의 풀이

def solution(keymap, targets):
    dic = {}
    answer = []

    for key in keymap:
        for idx, val in enumerate(key):
            if val not in dic or dic[val] > idx + 1:
                dic[val] = idx + 1
    
    for target in targets:
        count = 0

        for word in target:
            if word in dic: count += dic[word]
            else:
                count = -1
                break

        answer.append(count)    
  
    return answer

 

🧞‍♂️ 다른 사람의 풀이

def solution(keymap, targets):
    answer = []

    for target in targets:
        c = 0
        for t in target:
            r = min(list(map((lambda x: x.index(t) + 1 if t in x else 102), keymap)))
            if r == 102:
                answer.append(-1)
                break
            else:
                c += r
        if r != 102:
            answer.append(c)          

    return answer

 

 

 

🔗 https://wikidocs.net/16

02-5 딕셔너리 자료형

🔗 https://school.programmers.co.kr/learn/courses/30/lessons/160586

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